Question

[(6^2)×(−3)^2]^2÷[(4^2×3^2)×(1^1+0^1+2^1)^2]


Answer is in fractions

Answer 1

Answer:

My Answer is 324

Step-by-step explanation:

Tell me if it is correct or not

Answer 2

$\sf \large \underline{Concept:-}$

• Above question is based on exponents and powers. Let understand the question, in the question we have asked to find the value of [ (6²) × (–3)²]² ÷ [(4²×3²) × (1¹+0¹+2¹)²]. So, Let's start solving the problem

$\sf \large \underline{Given \: \: expression:-}$

$\sf { \bold {[ (6²) × (–3)²]² ÷ [(4²×3²) × (1¹+0¹+2¹)²] }}$

$\sf \bold{= (36×9)² ÷ [(16×9)×(1+0+2)²]}$

$\sf \bold{=(36² × 9²) ÷ [(16×9) × (3)²]}$

$\sf \bold{= 36×36×9×9 ÷ 16×9×9}$

$\sf \bold{ = \frac{36 \times 36 \times \cancel{ 9 }\times \cancel{ 9}}{16 \times \cancel{ 9} \times \cancel{ 9}} }$

$\sf \bold{= \frac{ \cancel4 \times 9 \times \cancel 4 \times 9}{ \cancel4 \times \cancel 4} }$

$\sf{ \bold \red {= 81}}$