Question

6^-2 +(3/2)^-2, simply ​

Answer 1

Answer:

$\dfrac{17}{36}$

Step-by-step explanation:

$6^{-2} + \bigg(\dfrac{3}{2} \bigg)^{-2}$

$=\bigg(\dfrac{1}{6} \bigg)^2 + \bigg(\dfrac{2}{3} \bigg)^{2}$

$=\dfrac{1}{6^2}+\dfrac{2^2}{3^2}$

$=\dfrac{1}{36}+\dfrac{4}{9}$

$=\dfrac{1}{36}+\dfrac{4 \times 4}{9 \times 4}$

$=\dfrac{1}{36}+\dfrac{16}{36}$

$=\dfrac{1 + 16}{36}$

$=\dfrac{17}{36}$