Question

√6/√2+√3 + 3/√6+√3 - 4√3/√6+√2
can anyone solve this
please!!!!!!!!!!!!!!!!!!!

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

First rationalize the denominator of each term by multiplying its conjugate in both the numerator and denominator and simplify it.

Conjugate of a first term (√2+√3) is√2-√3)

Conjugate second term (√6+√3) is (√6-√3)

Conjugate of third term (√6+√2) is (√6-√2)

In denominator FORMULA used= (a+b)(a-b)= a² - b²

Hopes it's helps you