Question

√6/√2+√3=a√3+b√2 find the value of (a-b)

Answer 1

Answer:

√6/√2+√3= a√3+b√2

Solving LHS

√6/√2+√3 *√2-√3/√2-√3

= √6(√2-√3)/(√2)²-(√3)²

= 2√3-3√2/2-3

= 2√3-3√2/-1

=-(2√3-3√2)

= -2√3+3√2

This is the answer .... Hope it helps you