Question

6+√2 is an irrational number prove it

Answer 1

Step-by-step explanation:

First let 6+root 2 is rational no.

Then

6+root 2=p/q(where p and q are integers)

Root2=p/q-6

Here

L. H. S which is root 2 is rational and on r. H. S where p q 6 are rational no

here contradiction arise as l. H. S is not equal to rhs

Therefore it is a irrational number.