Question

6×22.4 lit of co2 reacts with 6×18 gm of H2o to form 180 gm of h²o to form 180 gm of c6h12o6 and 6×22.4 lit of oxygen (stp)​

Answer 1

Answer:

The maximum number of molecules is present in 15 L of H

2

gas at STP.

1 mole of a gas at STP occupies a volume of 22.4 L.

15 L of gas corresponds to

22.4L

15L

=0.67 moles.

(B) 5 L of N

2

gas at STP :

1 mole of a gas at STP occupies a volume of 22.4 L.

5 L of gas corresponds to

22.4L

5L

=0.22 moles.

(C) 0.5 g of H

2

gas (molecular weight 2 g/mol) corresponds to

2g/mol

0.5g

=0.25 moles.

(D) 10 g of O

2

gas (molecular weight 3 g/mol) corresponds to

32g/mol

10g

=0.3125 moles.

Higher is the number of moles of a gas, higher will be its number of molecules.

Therefore, the correct option is A.

Answered By

toppr

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