Question

6×22 .4 lit of Co2 reacts with 6×18gm of H2O to form 180 gm of C6H12O6 and 6×22.4 lit of oxygen (STP)
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Answer 1

Answer:

Molecular formula =C

6

H

12

O

6

Molar mass =6×12+12×1+16×6=180gmol

−1

Moles in 18g of sample=

180

18

=0.1mole

So,moles of carbon present in sample=0.1×6=0.6

Moles of hydrogen=0.1×12=1.2

Moles of oxygen=6×0.1=0.6

No. of atoms present in carbon=0.6×6.022×10

23

=3.6×10

23

No. of atoms present in hydrogen=1.2×6.022×10

23

=7.2×10

23

No. of atoms present in oxygen=0.6×6.022×10

23

=3.6×10

23