Question

6÷∛24 - rationalize the denominator

Answer 1

Here's your answer..

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Answer 2

Answer:

$\sqrt[3]{9}$

Step-by-step explanation:

$6 \div \sqrt[3]{24} \\ = \frac{6}{ \sqrt[3]{ {2}^{3} \times 3 } }{ \times \frac{ \sqrt[3]{ {3}^{2} } }{ \sqrt[3]{ {3}^{2} } } } \\ = \frac{6 \times \sqrt[3]{ {3}^{2} }}{ \sqrt[3]{ {2}^{3} \times {3}^{3} } } \\ = \frac{6 \times \sqrt[3]{9} }{6} \\ = \sqrt[3]{9}$