Question

6.25*10^12 electrons were removed from a glass rod. What is the magnitude of positive charge acquired by the glass rod?

Answer 1

Answer: Since electrons are removed so the body will be positively charged .

1 electron contains(- 1.6*10^(-19))C so positively charged gained by the body will be equal to (25*10^12)*(1.6*10^(-19)) = 4*10^(-6)C

Explanation:

In glass rod when there is equal number of electron and proton then its charge will be neutral .

But when any particle(electron or proton) is more than the other, there is an unbalance in charge and thus the body becomes charged.1 electron contains(- 1.6*10^(-19))C so positively charged gained by the body will be equal to (25*10^12)*(1.6*10^(-19)) = 4*10^(-6)C. (C is coulomb)

Answer 2

Answer: 1× 10^-6

Explanation:

n=q/e , q=n×e

(6.25×10^12 ) × (1.6 ×10^-19) = 1×10^-6