6.25 x10^18 electrons are passing in time interval of 2 seconds through a conductor. Find the current flowing through it
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Answer:
current flowing will be 0.5 Ampere
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Given:
6.25 x10^18 electrons are passing in time interval of 2 seconds through a conductor.
To find:
Find the current flowing through it
Solution:
From given, we have,
6.25 x10^18 electrons are passing in the time interval of 2 seconds through a conductor.
The current is the rate of flow of charges.
The formula for calculating the amount of current, given the charge and time is,
I = Q/t
where, Q = ne
n is the number of charges
Therefore, we have,
I = Q/t = ne/t
I = (6.25 × 10^18 × 1.6 × 10^{-19}) / 2
I = 10 × 10^{-1} / 2
I = 0.5 A
Therefore, the current flowing through the conductor is 0.5 A.
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