Question

6^2n+1 ÷ 36 = 6^3
then find the value of n.

Answer 1

hope you get it......

Answer 2

Heya!
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♦Given that =>
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$= > \frac{6 {}^{2n + 1} }{36} = 6 {}^{3} \\ \\ = > \frac{6 {}^{2n + 1} }{6 {}^{2} } = 6 {}^{3} \\ \\ = > 6 {}^{2n + 1 - 2} = 6 {}^{3} \\ \\ = > 6 {}^{2n - 1} = 6 {}^{3} \\ \\ = > putting \: powers \: eq. \: since \: base \: is \: same \\ \\ = > 2n - 1 = 3 \\ \\ = > 2n = 4 \\ \\ = > n = 2$
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