Question

6(2x+1)²-(2x+1) - 5=0
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Answer 1

Answer:

x = -1

Step-by-step explanation:

on simplifying we get,

$6(4x^2+1+4x) - (2x + 1) - 5 = 0\\24x^2 + 6 + 24x - 2x-1-5=0\\24x^2+24x=0\\24x(x+1)=0\\x+1=0\\x=-1$

Therefore x = -1

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Answer 2

$\green{\bold{\underline{ ☆ UPSC-ASPIRANT ☆} }}$

$\red{\bold{\underline{\underline{QUESTION:-}}}}$

6(2x+1)²-(2x+1) - 5=0

$\huge\bigstar\huge\tt\underline\red{ᴀɴsᴡᴇʀ }\bigstar$

$6( {2x + 1)}^{2} - (2x + 1) - 5 = 0$

$6[( {2x)}^{2} + 1 + 2(2x)(1) ]- (2x + 1) - 5 = 0$

$24 {x}^{2} + 6 + 24x - 2x - 1 - 5 = 0$

$24 {x}^{2} + 24x - 2x + 6 - 1 - 5 = 0$

$24 {x}^{2} + 22x + 0 = 0$

$2(12 {x}^{2} + 11x) = 0$

$12 {x}^{2} + 11x = 0$

$x(12x + 11) = 0$

$12x = - 11$

$x = - \frac{11}{12}$

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