Math, asked by amaanjaved6875, 1 year ago

6^2x+1÷36=216 find the value of x

Answers

Answered by sushant2505
310
Hi...☺

Here is your answer...✌

 {6}^{2x + 1}   \div 36 = 216 \\  \\  {6}^{2x + 1}  = 216 \times 36 \\  \\  {6}^{2x +1 }  =  {6}^{3}  \times  {6}^{2}  \\  \\  {6}^{2x + 1}  =  {6}^{5}  \\  \\    equating \: th e\: power \: of \: 6 \\ we \: get \\  \\ 2x + 1 = 5 \\  \\ 2x = 5 - 1 \\  \\ 2x = 4 \\  \\ x = 2
Answered by rafatsk765rafat
23

Answer:

$$\begin{lgathered}{6}^{2x + 1} \div 36 = 216 \\ \\ {6}^{2x + 1} = 216 \times 36 \\ \\ {6}^{2x +1 } = {6}^{3} \times {6}^{2} \\ \\ {6}^{2x + 1} = {6}^{5} \\ \\ equating \: th e\: power \: of \: 6 \\ we \: get \\ \\ 2x + 1 = 5 \\ \\ 2x = 5 - 1 \\ \\ 2x = 4 \\ \\ x = 2\end{lgathered}$$

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