Math, asked by akshay2316, 4 months ago

(6 - 2y + 4z)2. it is icse question guy's

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Answered by loparathod2609

2

Answer:

Using (a + b + c)2 = a2 + b2 + c2 + 2ab + 2bc + 2ac. →(6-2y+4z)2 = (6)2 + (-2y)2 + (4z)2 + 2(6)(-2y) + 2(-2y)(4z) + 2(6)(4z). = 36 + 4y2 + 16z2 ...

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