Question

√6/√3-√2
Rationalize the denominator.
Please give the answer fast! ​

Answer 1

Answer:

$\frac{ \sqrt{6} }{ \sqrt{3} - \sqrt{2} } \times \frac{ \sqrt{3} + \sqrt{2} }{ \sqrt{3} + \sqrt{2} } \\ = \frac{ \sqrt{18} + \sqrt{12} }{3 - 2} \\ = 3 \sqrt{2} + 2 \sqrt{3}$

Hey! Mate Here is your solution. Thanks