Question

6.) 3.42g of Sucrose are dissolved in
18g of water in a beaker. The number of orygen atoms in the solution are
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Answer 1

Answer:

Number of moles = 0.01 Sucrose(C12H22O11) contains 11 oxygen atoms ⇒11 x 6.022 x 1023 For 0.01 moles of sucrose ⇒ 0.01 x 11 x 6.022 x 1023 Now, Molar mass of water = H2O = 2 × 1 + 16 = 18g/mol ⇒ Number of moles = 1 Sucrose (H2O) contains 1 oxygen atom = 6.022 × 1023 For 1 mole of water = 6.022 × 1023 Now, add the both values: 6.6 × 1022 + 6.022 × 1023 We get 6.68 × 1023