Question

6÷3×√(6)−2×√(3)= 3×√(2)−a√(3), find the value of a.​

Answer 1

Answer:

$given = \frac{6}{ \sqrt[3]{2} - \sqrt[2]{3} } = \sqrt[3]{2} - \sqrt[a]{3}$

$to \: find = value \: of \: a$

$solution$

$\frac{6}{ \sqrt[3]{2} - \sqrt[2]{3} } \times \frac{ \sqrt[3]{2} + \sqrt[2]{3} }{ \sqrt[3]{2} + \sqrt[2]{3} }$

$(rationalise \: the \: denominator)$

$=> \frac{6( \sqrt[3]{2} + \sqrt[2]{3}) }{18 - 12}$

$\frac{6( \sqrt[3]{2} + \sqrt[2]{3}) }{6}$

$\frac{ \sqrt[3]{2} + \sqrt[2]{3} }{1}$

$a = - 2$

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