Math, asked by deepjyotibala5, 11 hours ago

6+√3 6-√3 find
the given value of a equation.​

Answers

Answered by Sushant10genius
0

Answer:

(6+√3) (6-√3)= 6²-(√3)² | (a+b)(a-b)=a²-b²

= 36-3

= 33

Answered by lokitagoyal9812
0

(6+√3)(6-√3)

=(6)^2 - (√3)^2. ( a^2- b^2 = (a+b) (a-b))

= 6 × 6 - √3 × √3

= 36-3

= 33

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