Question

6+√3÷6−√3 plz solve this question ​

Answer 1

This is ur required answer...

Answer 2

Answer:

$\frac{6 + \sqrt{3} }{6 - \sqrt{3} } \\ \\ = \frac{6 + \sqrt{3} }{6 - \sqrt{3} } \times \frac{6 + \sqrt{3} }{6 + \sqrt{3} } \\ \\ = \frac{(6 + \sqrt{3}) ^{2} }{(6) ^{2} - ( \sqrt{3} ) ^{2} } \\ \\ = \frac{(6)^{2} + 2 \times 6 \times \sqrt{3} + ( \sqrt{3} ) ^{2} }{36 - 3} \\ \\ = \frac{36 + 12 \sqrt{3} + 3 }{33} \\ \\ = \frac{39 + 12 \sqrt{3} }{33} \\ \\ = \frac{3(13 + 4 \sqrt{3} )}{33} \\ \\ = \frac{13 + 4 \sqrt{3} }{11} \\ \\ \\ formula \: used \: \\ \\ (a + b) ^{2} = a^{2} + 2 ab + b ^{2} \\ \\ a ^{2} - b ^{2} = (a + b)(a - b)$

hope it helps uH ✔