Question

6+(-3) + 7 - [8 - {6 ÷ 3-(6-9÷3)÷ 3}].​

Answer 1

Starting from the inner most bracket

= 6-3 + 7 -[8-{6÷3-(6-3)÷3}]

= 6-3+7-[8-{6÷3-6÷3}]

= 6-3+7-[8-{2-2}]

= 6-3+7-[8-0]

= 6-3+7-8

= 13-11

= 2

Here the BODMAS rule is followed and each innermost bracket is solved first.

This is ur answer please mark as brainliest!!

Answer 2

Answer:

ok so,

6+(-3)+7-[8-{6÷3-(6-9÷3)÷3}]

= 3+7-[8-{6÷3-(6-9÷3)÷3}]

=10-[8-{6÷3-(6-9÷3)÷3}]

=10-[8- {2-(6-3)÷3}]

=10-[8-{2-1}]

=10-7

=3

Step-by-step explanation:

1. as like 6+(-3) equals to 3 of course

2. 7+3= 10

3. 6÷3=2 and 9÷3=3

4. 6-3=3 and 3÷3=1

5. 2-1=1 and 8-1=7 then

i hope this helped you :)