Question

6.3 g of crystalline oxalic acid present in 100 ml of solution find molarity and normality​

Answer 1

Answer:

0.4

Explanation:

M = given weight (g)/1000/ v (ml)

M = 4.9 / 98 × 1000

= 4 /20

= 0.2

N= M × n - factor

= 0.2 × 2 = 0.4 hope its help u......TC❤