6.3 g of oxalic acid is dissolved in the 500g of H20. Find the molality of the solution . (molar mass of oxalic acid 120g/mol)
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Answer:
Normality is defined as the number of mole equivalents per litre of solution.
Oxalic acid C
2
H
2
O
4
.2H
2
O
Molecular mass =126g
Equivalent weight =
2
126
=63g/equiv
Normality =
Eq. wt. ×1000
weight
=
63×
1000
500
6.3
=0.1×2=0.2N
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