Question

6√(3)x^2+7x-√(3)=0
Factorise this equation and get answer in integers or fraction

Answer 1

Answer :

Given,

6√3x² + 7x - √3 = 0

➠ 6√3x² + 9x - 2x - √3 = 0

➠ 3√3x (2x + √3) - 1 (2x + √3) = 0

➠ (2x + √3) (3√3x - 1) = 0

So, 2x + √3 = 0, or, 3√3x - 1 = 0

∴ The required solution be

x = (- √3/2), 1/(3√3)

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Answer 2

Given,

It is given that 6√3x² + 7x -√3 = 0.

To find,

We have to find the factors of 6√3x² + 7x -√3.

Solution,

The factors of 6√3x² + 7x -√3 are -√3 /2 and 1/3√3 .

We can simply find the factors of 6√3x² + 7x -√3 by using splitting the middle term method.

      = 6√3x² + 7x -√3

      = 6√3x²+ 9x-2x-√3

Taking 3√3x common from first two terms and -1 from last two terms, we get

      = 3√3 x(2x + √3 )-1(2x+√3)

Taking (2x+√3) common, we get

     = (2x+√3) (3√3x-1)

⇒ Either first expression is zero or last expression is zero, we get

     x = -√3 /2 , x = 1/3√3

Hence, the factors of 6√3x² + 7x -√3  are -√3 /2 and 1/3√3.