Question

-
6(3 x 4 = 6) + 13[3 – 2{4 + 2
– (6 x 2 – 3 x 5 + 6 - 2 x 3)}]​

Answer 1

Step-by-step explanation:

The given equations are

⇒

x+3

16

+

y−2

3

=5....eq(1)

⇒

x+3

8

−

y−2

1

=0....eq(2)

Put

x+3

1

=u and

y−2

1

=v in eq(1)and(2)

⇒16u+3v=5....eq(3)

⇒8u−v=0....eq(4)

multiply eq(4) by 3 and subtract eq(3)and eq(4)

⇒(16u+3v=5)−(24u−v=0)

⇒40u=5⇒u=

8

1

Putu=

8

1

in eq(3)

⇒16(

8

1

)+3v=5⇒3v=3⇒v=1

Hence,

x+3

1

=u=

8

1

1. ⇒x+3=8⇒x=5

y−2

1

=v=1⇒y−2=1⇒