Question

6√32 − 8√72 + √242 − √2
simplify the following surds​

Answer 1

Answer:

$given \: that \: 6. \sqrt{32} - 8 \sqrt{72} + \sqrt{242} - \sqrt{2}$

$= 6. \sqrt{ {4}^{2} \times 2 } - 8 \sqrt{ {6}^{2} \times 2} + \sqrt{ {11}^{2} \times 2} - \sqrt{2}$

$= 6 \times 4 \sqrt{2} - 8 \times 6 + 11 \sqrt{2} - \sqrt{2}$

$= \sqrt{2} \times (24 - 48 + 11 - 1)$

$= - 14 \sqrt{2}$

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