Question

(6) 39p3(50p2 – 98) + 26p2(5p + 7)​

Answer 1

Step-by-step explanation:

• Given data

        $\mathbf{39P^{3}(50P^{2}-98)+26P^{2}(5P+7)}$

        Opening bracket

        $\mathbf{39P^{3}\times 50P^{2}-39P^{3}\times 98+26P^{2}\times 5P+26P^{2}\times 7}$

        $\mathbf{39\times 50\times P^{3}\times P^{2}-39\times 98\times P^{3}+26\times 5\times P^{2}\times P+26\times 7\times P^{2}}$

• $\mathbf{1950\times P^{5}-3822\times P^{3}+130\times P^{3}+182\times P^{2}}$

        We can also write above equation in this way

        $\mathbf{1950P^{5}-3822P^{3}+130P^{3}+182P^{2}}$

• Means

       $\mathbf{39P^{3}(50P^{2}-98)+26P^{2}(5P+7)=1950P^{5}-3822P^{3}+130P^{3}+182P^{2}}\mathbf{}$

Answer 2

$1950p^{5} - 3822p^{3} + 130p^{3} + 182 p^{2}$

Step-by-step explanation:

We have to simplify the expression as given below:

$39p^{3}(50p^{2} - 98) + 26p^{2}(5p + 7)$

Now,

$39p^{3}(50p^{2} - 98) + 26p^{2}(5p + 7)$

= $39p^{3}\times 50p^{2} - 39p^{3}\times 98 + 26p^{2}\times 5p + 26p^{2}\times 7$

{Applying distributive property of multiplication}

= $(39 \times 50) p^{3 + 2} - (39 \times 98) p^{3} + (26 \times 5) P^{2 + 1} + (26 \times 7) p^{2}$

= $1950p^{5} - 3822p^{3} + 130p^{3} + 182 p^{2}$ (Answer)