6.3g of oxalic acid (126) is added to 0.5M 500mL oxalic acid solution. Find the resultant molarity.
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Molar mass of Oxalic acid (H
2
C
2
O
4
.2H
2
O)=126
Molarity=
Volume of the solution in mL
(
Molar mass
Mass of solute in grams
)×1000
Molarity=
100
(
126
12.6
)×1000
Molarity=1 M
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