Question

6(3x+2)-5(6x-1)=2(x-8)-5(7x-6)+8x

Answer 1

18x+12-30x+5=2x-16-35x+30+8x
-12x+17=-25x+14
13x=-3
x=-3/13

Answer 2

Answer:

Required value of x is

$(- 4 \frac{11}{13} )$

Step-by-step explanation:

Given,

$6(3x+2)-5(6x-1)=2(x-8)-5(7x-6)+8x$

This is a problem of Algebra.

Here first we are removing first bracket,

$18x + 12 - 30x + 5 = 2x - 16 - 35x - 30 + 8x$

We are separating variable and constant part,

$18x - 30x - 2x + 35x - 8x = - 16 - 30 - 12 - 5$

$13x = - 63$

So,

$x = - \frac{63}{13} = - 4 \frac{11}{13}$

Required answer is

$(- 4 \frac{11}{13} )$

Some important formulas of Algebra,

a + b)² = a² + 2ab + b²

(a − b)² = a² − 2ab − b²

(a + b)³ = a³ + 3a²b + 3ab² + b³

(a - b)³ = a³ - 3a²b + 3ab² - b³

a³ + b³ = (a + b)³ − 3ab(a + b)

a³ - b³ = (a -b)³ + 3ab(a - b)