Question

6(3x+2)-5(6x-1)=3(x-8)-5(7x-6)+9x

Answer 1

Answer:

Value of x = -1

Step-by-step explanation:

Given simple equation :

6(3x+2)-5(6x-1)=3(x-8)-5(7x-6)+9x

=> 18x+12 - 30x +5 = 3x - 24 - 35x + 30 + 9x

=> 18x-30x+12+5 = 3x-35x+9x-24+30

=> 18x-30x -3x +35x -9x = -24+30-12-5

=> (18-30-3+35-9)x = 30 - 41

=> (53-42)x = -11

=> 11x = -11

/* Divide each term by 11, we get

=> x = -1

Therefore,

Value of x = -1

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Answer 2

Here it is given that,

We have to find the value of the given expression

$6(3x+2)-5(6x-1)=3(x-8)-5(7x-6)+9x$

To solve this expression we have to use the rule of BODMAS,

Expand the parentheses:

$=>6 \times 3x + 6 \times 2 - (5\times (6x - 1)) = 3(x - 8) - 5(7x - 6) + 9x$

Simplifying it we get,

$=>18x + 12 - (5(6x - 1)) = 3(x - 8) - 5(7x - 6) + 9x$

$=>18x + 12 - (5 \times 6x + 5 \times - 1) = 3(x - 8) - 5(7x - 6) + 9x$

$=>18x + 12 - (30x - 5) = 3(x - 8) - 5(7x - 6) + 9x$

Now, again expanding the parenthesis

$=>18x + 12 - 30x + 5 = 3(x - 8) - 5(7x - 6) + 9x$

Grouping the like terms,

$=>(18x - 30x) + (12 + 5) = 3(x - 8) - 5(7x - 6) + 9x$

Simplifying it we get,

$=>- 12x + (12 + 5) = 3(x - 8) - 5(7x - 6) + 9x\\=>- 12x + 17 = 3(x - 8) - 5(7x - 6) + 9x$

Now, solve by distributing,

$=>- 12x + 17 = 3x + 3 \times - 8 - (5(7x - 6)) + 9x\\=>- 12x + 17 = 3x - 24 - (5(7x - 6)) + 9x$

Group the like terms, we get

$=>- 12x + 17 = (3x + 9x) - 24 - (5(7x - 6))\\=>- 12x + 17 = 12x - 24 - (35x - 30)\\=>- 12x + 17 = (12x - 35x) + (- 24 + 30)\\=>- 12x + 17 = - 23x + 6$

Add $23$ on both the sides we get,

$=>- 12x + 17 + 23x = - 23x + 6 + 23x\\=>- 12x + 23x + 17 = - 23x + 6 + 23x\\=>11x + 17 = - 23x + 6 + 23x\\=>11x + 17 = 6$

Subtract both sides by $17$ we get,

$=>11x + 17 - 17 = 6 - 17\\=>11x = 6 - 17\\=>11x = - 11$

Now, divide both sides by $11$ we get,

$=>x=\frac{-11}{11}$

For the numerator and the denominator, we have to find the GCF,

$=>x=\frac{-1\times 11}{1\times11}\\=>x=-1$

Hence, the required solution is $-1.$