Question

6(3x + 2) - 5(6x - 1) = 3(x - 8) - 5(7x - 6) + 9x​

Answer 1

Step-by-step explanation:

The above question can be written as,= 18x + 12 – 30x + 5 = 3x – 24 – 35x + 30 + 9x Now, find the value of x by considering the above equation, Transposing 12, 5 to RHS and it becomes -12, -5 and -35x, 9x, 3x to LHS it becomes 35x, -9x, -3x = 18x – 30x + 35x – 9x – 3x = -24 + 30 – 12 – 5 = 53x – 42x = 30 – 41 = 11x = -11 Multiplying both side by (1/11), = 11x × (1/11) = -11 × (1/11) = x = (-11/11) = x = -1 By substituting 5 in the place of x in given equation, we get LHS, = 18x + 12 – 30x + 5 = 18 (-1) + 12 – 30 (-1) + 5 = -18 + 12 + 30 + 5 = -18 + 47 = 29 RHS, = 3x – 24 – 35x + 30 + 9x = 3 (-1) – 24 – 35 (-1) + 30 + 9 (-1) = -3 – 24 + 35 + 30 – 9 = -36 + 65 = 29 By comparing LHS and RHS = 15 = 15 ∴ LHS = RHS

Answer 2

Given,

$6(3x+2)-5(6x-1)=3(x-8)-5(7x-6)+9x$

we have to find the value of $x$

First simplify the given expression after that take $x$ terms in LHS side and constant terms in RHS side

Now,

$6(3x+2)-5(6x-1)=3(x-8)-5(7x-6)+9x\\18x+12-30x+5=3x-24-35x+30+9x\\17-12x=6-23x\\23x-12x=6-17\\11x=-11\\x=-1$

Therefore, the value of $x$ is $-1$.