Math, asked by Tusharnandy, 11 months ago

6+√3x^2+7x=√3 solve by factorisation method only

Answers

Answered by swatiskulkarni
20

Answer:

6√3x²+7x=√3

6√3x²+7x-√3=0

6√3x²+9x-2x-√3=0

3√3x(2x+√3)-1(2x+√3)=0

(2x+√3)(3√3x-1)=0

X= -√3/2 or X= 1/3√3

#hopeithelps

Answered by iiii387
2

Answer:

it's your answer

I hope it's help you

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