Question

6 - 3x/3- 5x+12/4 = -1​

Answer 1

Step-by-step explanation:

$question : \bold \red{\frac{6 - 3x}{3 - 5x} + \frac{12}{4} } = \pink{ - 1} \\ = > \bold \red{ \frac{6 - 3x}{3 - 5x} + 3} = \pink{ - 1} \\ = > \bold \red{ \frac{6 - 3x}{3 - 5x} } = \pink{ - 1 - 3} \\ = > \bold \red{ \frac{6 - 3x}{3 - 5x} } = \pink{ - 4} \\ = > \bold \red{6 - 3x} = \pink{ - 4(3 - 5x)} \\ = > \bold \red{6 - 3x} = \pink{ - 12 + 20x} \\ = > \bold \red{ - 3x - 20x} = \pink{ - 12 - 6} \\ = > \bold \red{ - 23x} = \pink{ - 18} \\ = > \blue{x} = \pink { \frac { - 18} { - 23} } = \pink{ \frac{18}{23} }. \\ \therefore \blue{x} = \pink{ \frac{18}{23}}.$