Question

6√3x²-47x+5√3 factorise it

Answer 1

6\/3x^2-47x+5\/3
6\/3x^2-45x-2x+5\/3
3\/3x(2x-5\/3x) - 1(2x-5\/3)
(3\/3x - 1)(2x - 5\/3x)

Answer 2

Answer:

(3√3x - 1)(2x - 5√3)

Step-by-step explanation:

Given equation is

6√3x² - 47x + 5√3

In order to factorize the above expression we have to use the middle term breaking method. So, the above equation will become

6√3x² - 45x - 2x + 5√3 .... (1

Now 45 can we written as

45 = 15 x 3 = 15 x (√3)² = 15√3√3

Replace 45 by 15√3√3 into equation 1

6√3x² - 15√3√3x - 2x + 5√3

grouping the terms

(6√3x² - 15√3√3x) - (2x - 5√3)

taking commons

3√3x(2x - 5√3) - 1(2x - 5√3)

taking common again

(3√3x - 1)(2x - 5√3)

This is our factorized form of the expression 6√3x² - 47x + 5√3 .