Question

6√3x²+47x+5√3

find factorisation​

Answer 1

Answer:

jajsbx. Anja s Sasidhar s bad s

Answer 2

Answer:

$\huge\mathbb{SOLUTION}$

$6 \sqrt{3} {x}^{2} + 47x + 5 \sqrt{3} = 0 \\ 6 \sqrt{3} {x}^{2} + 45x + 2x + 5 \sqrt{3} = 0 \\ 6 \sqrt{3} x^2+ 2x + 45x + 5 \sqrt{3} = 0 \\2x(3 \sqrt{3} x + 1) + 5 \sqrt{3} (3 \sqrt{3} x + 1) =0 \\(2x + 5 \sqrt{3})(3 \sqrt{3}x + 1) = 0 \\ 2x + 5 \sqrt{3} = 0 \: or \: 3 \sqrt{3} x + 1 = 0 \\ x = \frac{ - 5 \sqrt{3} }{2} or \: x = \frac{ - 1}{3 \sqrt{3} }$