6(3x4÷6)+13[3-2{4+2-(6x2-3x5+6-2x3)}]
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this answer can solve with BODMAS
tinwalaqusai:
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Answered by
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6×12+[1{6-(12-15+4×3)}]
=72+[1{6-(-3+12)]}]
=72+[1{6-9)}]
=72+[-3]
=72-3
=69
=72+[1{6-(-3+12)]}]
=72+[1{6-9)}]
=72+[-3]
=72-3
=69
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