Question

6 (3y+ 5) = 2 (2 y + 1)​

Answer 1

6 (3y+ 5) = 2 (2 y + 1)

( 18y + 30 ) = ( 4y + 2)

18y - 4y = 2 - 30

14 y = -28

y = -28/14

y = -2