6.4 In Fig. 85, ABCD is a parallelogram in which AB = 20 cm, AD = 15 cm, and altitude AE = 12 cm. Find the length of the altitude corresponding to side AD.
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Step-by-step explanation:
For the first triangle, given that
Base = 15 cm and altitude = 7 cm
We know that area of a triangle = ½ (Base x Altitude)
= ½ (15 x 7)
= 52.5 cm^2
It is also given that the area of the first triangle and the second triangle are equal.
Area of the second triangle = 52.5 cm^2
One side of the second triangle = 10.5 cm
Therefore, The other side of the second triangle = (2 x Area)/One side of a triangle
= (2x 52.5)/10.5
=10 cm
Hence, the other side of the second triangle will be 10 cm.
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