Question

6
*(4) The masses of the earth and moon are
6 x 1024 kg and 7.4 x 1022 kg, respectively. The
distance between them is 3.84 x 105 km.
Calculate the gravitational force of attraction
between the two. Use G = 6.7 x 10-11 N·m² kg
2
- 2​

Answer 1

Answer:

2.02*10to the power 20 N.

Explanation:

solution :

The mass of the earth, m= 6*10to the power 24.kg

the mass of the moon, m=7.4*10to the power

22.kg

The distance between the earth and the moon,

d=3.84*10to the power 5 .km

d=3.84*10 to the power 5. 1000 m

d=3.84*10 to the power 8.m

G= 6.7*10 to the power -11 n m square kg-2

The force extended by the earth and moon is

F=G(M*m/d square)

= 6.7*10 to the power -11. N m square kg square * 6*10 to the power 24.kg*7.4*10to the power 22kg

_______________________________

(3.84*10 to the power 8 m) square

= 2.02 * 10 to the power 20 N.

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Answer 2

$\huge \sf {\fbox{\fbox{\red{\fbox{Answer:}}}}}$

$\huge \bf{Given:-}$

$\sf {→Mass \: of \: the \: earth,m_1 = 6 \times{{10}^{24} }}$

$\sf {→Mass \: of \: the \: moon,m_2 = 7.4\times{{10}^{22} }}$

$\sf {→Distance \: between \: the \: earth \: and \: moon,r = 3.84\times{{10}^{5} }}$

$\sf {→Distance \: between \: the \: earth \: and \: moon,r = (3.84\times{{10}^{5} \times 1000)m }}$

$\sf {→Distance \: between \: the \: earth \: and \: moon,r = 3.84\times{{10}^{8}m}}$

$\huge \bf{To \: find:- }$

$\sf{⇒Force \: exerted \: to \: one \: body \: to \: another \: body.}$

$\huge \bf{Formula \: used: - }$

$\leadsto\sf{F =G \times \frac{m_1 \times m_2}{r^2} }$

$\huge \bf{Concept \: used: - }$

$\sf{Gravitational \: constant,G=6.7 \times {10}^{- 11N} N{m}^{2}k {g}^{ - 2} }$

$\huge\bf{According \: to \: Question:-}$

$\bf{F = \frac{6.7 \times {10}^{ - 11} \times 6 \times {10}^{24} \times 7.4 \times {10}^{22}} {(3.84 \times {10}^{8} )^{2} } = 2.01 \times {10}^{20} newtons}$

$\sf\longmapsto{2.01 \times {10}^{20} newtons}$

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