Question

6.4
∆U°of combustion of methane is - X kJ mol-l. The value of AH is
(i) = ΔU9
(ii) > AU
(iii) < AU
(iv) = 0​

Answer 1

Answer:

CH  

4

​  

(g)+2O  

2

​  

(g)⟶CO  

2

​  

(g)+2H  

2

​  

O(l)

Now,

Δn  

g

​  

=(n  

p

​  

−n  

r

​  

)=1−3=−2

Again,

ΔH  

o

=ΔU  

o

+Δn  

g

​  

RT

ΔH  

o

=−X−2RT

∴ΔH  

o

<ΔU  

o

Explanation: