Question

(6/42)^3*(7/9)^2. Evaluate. ​

Answer 1

Answer:

$( \frac{6}{42} ) {}^{3} \times( \frac{7}{9} ) {}^{2} \\ = ( \frac{6 \times 6 \times 6 \times 7 \times 7}{42 \times 42 \times 42 \times 9 \times 9 } = \frac{1}{7 \times 81} \\ = \frac{1}{567} \: \: ans$

Hey! Mate Here is your solution. Thanks