Question

6/42power3×7/9power2​

Answer 1

Answer:

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Step-by-step explanation:

${( \frac{6}{42}) }^{2} \times { (\frac{7}{9}) }^{2} \\ = > { (\frac{1}{7} )}^{2} \times (\frac{49}{81} ) \\ = > \frac{1}{49} \times \frac{49}{81} \\ = > \frac{1}{81} = \frac{1}{ {9}^{2} } = {9}^{ - 2}$