6.44 * 10^-2 kg of hydrated sodium sulphate (Na2SO4.xH2O) is dissolved in water to obtain a 1 dm^3 solution. If the molarity of the solution with respect to Na2So4 is 0.2M then the value of x is
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Answer:
10
Explanation:
Given data:
wight of na2so4.xh2o--> 6.44 * 10^-2 kg
wight of solvent--> 1ml
Formula required : Molarity = weight of solute/molecular weight of solute*1000/vol. of solvent(ml)
Sub:
0.2= 6.44 * 10^-2 /mw *1000/1
--> molecular wt of solute =322kg
so if u take 10 moles h2o --you will get 322 kg of na2so4.10h2o (142+180=322)
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