Question

6(-4x) +7(2+5x) =53 Solve this equation.

Answer 1

Given:

• A linear equation is given to us.
• The equation is : 6(- 4x)+7(2+5x)=53.

To Find:

• The value of x .

Answer:

Here we are given a linear equation which is :

1. 6(-4x)+7(2+5x)=53.

Taking the given equation ,

$\red{\sf{\implies 6(-4x)+7(2+5x)=53}}$

$\sf{\implies -24x + 14+35x = 53}$

$\sf{\implies 35x - 24x = 53 -14}$

$\sf{\implies 11x = 39}$

${\underline{\boxed{\red{\sf{\leadsto x= \dfrac{39}{11}}}}}}$

Hence the value of x is 39/11.

$\rule{200}1$

Verification:

LHS = 6(-4x) +7(2+5x)

= 6(-4 × 39/11) +7(2 + 5×39/11)

= 6 × -156/11 + 7(2 + 195/11)

= -936/11 + 14 + 1365/11

=$\sf{\dfrac{-936+154+1365}{11}}$

= 583/11

= 53.

RHS = 53 .

Hence verfied.

Answer 2

▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬

$\huge\bold{\mathtt{QUESTION}}$

➡ Solve this equation -

6(-4x) +7(2+5x) =53

▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬

$\huge\bold{\mathtt{ANSWER}}$

↪ $\sf 6(-4x) +7(2+5x) = 53$

↪ $\sf -24x + 14 + 35x = 53$

↪ $\sf -24 + 11x = 53$

↪ $\sf 11x = 53-24$

↪ $\sf 11x = 39$

↪ $\large{\mathtt{\boxed{\boxed{\red{x = \dfrac{39}{11}}}}}}$

▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬