6+4y+y^2 and 8-5y+3y^2
Answers
Answered by
1
Step-by-step explanation:
6+4y+y^2
y^2+4y+6=0
compared with ay^2+by+c=0
a=1, b=4, c=6.
b^2-4ac=4^2-4*1*6
=16-24
= - 6
this equation roots are not real numbers
8-5y+3y^2
3y^2-5y+8=0
compaired with ay^2+by+c=0
a=3, b= -5, c=8
b^2-4ac= (-5)^2-4*3*8
=25-96
= -71
this equation roots are not real numbers
Similar questions