6 -5 1 1
If the matrix 4 4 2 -- 1 has no inverse, then
L14 -1 k
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1
Answer:
Correct option is
C
k
=−4
For a matrix to be invertible, its determinant must not be zero.
∴−1(5k+12)−3(5−(−3))+2(4−k)
=0
∴−5k−12−24+8−2k
=0
∴−7k
=28
∴k
=−4
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