Question

6) 5, 12, 19, 26 - 34th form at the AP is

an=a+(n-1)d
a34=5+33×7
a34=5+231
a34=236

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Answer 1

Here first term a=5 and common difference

d=12−5=7

Suppose nth term of the A.P. is 145.

Now, T

n =a+(n−1)d

∴145=5(n−1)(7)

∴145−5=7(n−1)

∴140=7(n−1)

∴20=n−1∴n=21

Answer 2

Answer:

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Step-by-step explanation:

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