Question

6-( 5×3-(-12)×16÷(-98) )​

Answer 1

$\huge\color{lime}\boxed{\colorbox{black}{Answer : - }}$

$6-(5 \times 3-(-12) \times 16 \div (-98))$

$Multiply \: 5 \: and 3 \: to \: get \: 15.$

$= > 6-\left(15-\frac{-12\times 16}{-98}\right)$

$Multiply \: -12 \: and \: 16 \: to \: get \: -192.$

$= > 6-\left(15-\frac{-192}{-98}\right)$

$Reduce \: the \: fraction \: \frac{-192}{-98} \: to \\ lowest \: terms \: by \: extracting \: and \\ canceling \: out \: -2.$

$= > 6-\left(15-\frac{96}{49}\right)$

$Convert \: 15 \: to \: fraction \: \frac{735}{49}.$

$= > 6-\left(\frac{735}{49}-\frac{96}{49}\right)$

$Since \: \frac{735}{49} \: and \: \frac{96}{49} \: have \: the \: \\ same \: denominator, \: subtract \: \\ them \: by \: subtracting \: their \: \\ numerators.$

$= > 6-\frac{735-96}{49}$

$Subtract \: 96 \: from \: 735 \: to \: get \: 639.$

$= > 6-\frac{639}{49}$

$Convert \: 6 \: to \: fraction \: \frac{294}{49}.$

$= > \frac{294}{49}-\frac{639}{49}$

$Since \: \frac{294}{49} \: and \: \frac{639}{49} \: have \: the \\ same \: denominator, \: subtract \\ them \: by \: subtracting \: their \\ numerators.$

$= > \frac{294-639}{49}$

$Subtract \: 639 \: from \: 294 \: to \: get \\ -345.$

$= > -\frac{345}{49}$

$\color{purple}\frac{{(-1)} \cdot 3 \cdot 5 \cdot 23}{7 ^ {2}} \approx -7.040816327$