Question

6√5 , √3 , 3√2 .
Plz Anyone Give me the answer of this que. explaining ​

Answer 1

Answer:

here is your answer mate...

Step-by-step explanation:

Given\: \frac{2\sqrt{6}-\sqrt{5}}{3\sqrt{5}-2\sqrt{6}}

=\frac{2\sqrt{6}-\sqrt{5}}{3\sqrt{5}-2\sqrt{6}}\times \frac{3\sqrt{5}+2\sqrt{6}}{3\sqrt{5}+2\sqrt{6}}

=\frac{2\sqrt{6}(3\sqrt{5}+2\sqrt{6})-\sqrt{5}(3\sqrt{5}+2\sqrt{6})}{(3\sqrt{5})^{2}-(2\sqrt{6})^{2}}

=\frac{6\sqrt{30}+24-15-2\sqrt{30}}{45-24}

=\frac{4\sqrt{30}+9}{21}

Therefore,

\frac{2\sqrt{6}-\sqrt{5}}{3\sqrt{5}-2\sqrt{6}}=\frac{4\sqrt{30}+9}{21}

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