Question

(6+√5) (6-√5) is rational number?
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Answer 1

Answer:

Yes

Step-by-step explanation:

use a^2-b^2 formula

then it becomes 36-5= 31

which can be written as 31/1 and therefore itbis rational

MARK MY ANSWER AS BRAINLIEST

Answer 2

Answer:

31

Explanation:

Using the identity, $a^{2} - b^{2} = (a+b)(a-b)$, where a = 6 and b = $\sqrt{5}$

$(6}+\sqrt{5}) (6-\sqrt{5})$

$= (6)^2-(\sqrt{5})^2$

$= 36 - 5$

$= 31$

31 is a rational number.