Math, asked by artivermalko7713, 1 year ago

√6+√5/√6-√5 number system and solved the problem

Answers

Answered by abhi569
1
 \frac{ \sqrt{6} +  \sqrt{5}  }{ \sqrt{6} - \sqrt{5} }
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 By Rationalization,




 \frac{ \sqrt{6}+  \sqrt{5}  }{ \sqrt{6} - \sqrt{5} } × \frac{ \sqrt{6}+ \sqrt{5}  }{ \sqrt{6} +  \sqrt{5} }


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On denominator,

By Formula, a^2 -b^2 = (a+b)(a-b)

On nominator,

By Formula, (a+b)^2 = a^2 + b^2 +2ab
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 \frac{ \sqrt{6}+  \sqrt{5}  }{ \sqrt{6}- \sqrt{5}  } × \frac{ \sqrt{6} +  \sqrt{5} }{ \sqrt{6}+  \sqrt{5} }



 \frac{( \sqrt{6}+  \sqrt{5})^2  }{( \sqrt{6})^2 -  (\sqrt{5})^2  }


Applying  Formula


 \frac{6 + 5 +  2\sqrt{30} }{6-5}



 \frac{11 + 2 \sqrt{30} }{1}



11 + 2 \sqrt{30}



i hope this will help you



-by ABHAY
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